This site was created by Justin Kelly, a student in AP Physics as a display of technology and its use in Physics.
If you have questions or would like commit write me at Justin123@juno.com.
This is a graph of the momentum of a 5 kg ball being dropped from rest
under earths gravity (momentum v. Time).
This is the window or range and domain of the above graph (window).
This is the data for the above graph with the above window.
A problem & answer
*A 13-g bullet traveling 230 m/s penetrates a 2.0-kg block of wood and emerges going 170 m/s. If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?
P at start p=mv m=.013kg
P=(.013kg)(230m\s) v=230m\s
P = 2.99 kg*m\s
P loss due to hitting board.
P=mv P=2.21 Kg*m/s
P=(.013)(170) M=(.013kg)
P=2.21 Kg*m/s V=170m/s
P loss Pi -Po =Ploss
.78 p is left for board (transferred to board)
P = mv p= .78 m=2.0kg
.78=(2.0)v
v=.39m/s
speed of board is .39m/s
*The above question comes from Chapter 7 question 11 of Giancoli Physics textbook fifth edition.